"15x20=300 watt hrs/12 volts=25 amp hrs x 2 (max 50% drain) = 50 amp hr + (how much for inverter draw?) = X amp hr battery needed."
up to this point you're ok,
"15x20=300 watt hrs/12 volts=25 amp hrs"
here's where you made a mistake,
"x 2 (max 50% drain) = 50 amp hr "
the max 50% drain gets subtracted from a lead acid battery not added to the load. you could add some to the load for inefficiencies, a little buffer, cloudy days, etc.
so you have a 25Ah load. like Elbear said a 100Ah lead acid would work fine. that would only use 50% of your available power or put another way it would take the battery down to 75%. you could take it down to 50% and be ok. that's where your 50% comes to play.
now for the big question,
how do you plan to charge this battery?
highdesertranger