A while back someone asked about measuring the wattage of an unknown solar panel. We can't do it in a controlled, laboratory environment but given a good sunny day you should be able to get close. You will need a DVM with an adequate amps scale (for 'adequate' it should be more than the guesstimated output of the panel else you may blow a fuse inside the DVM). I'd use the size of the Renogy 100 watt poly panel as a benchmark, since that is what I've got. The Renogy 100 watt polycrystalline panel is 40.5" X 26.7". A similar size panel should be comparable in specifications, smaller sized will probably be less watts, and larger will probably be more. A similarly sized 12 volt solar panel should have an open circuit voltage somewhere close to 20 volts and a short-circuit current of about 5 amps.
The height of summer is the best time to do this measurement since at any other time of year the sun will be lower and the sun's rays will be passing through more atmosphere, reducing their intensity. Just turning the panel to directly face the sun does not decrease the amount of atmosphere the sunlight passes through before hitting your panel! Measure the open-circuit voltage, and note the reading. Set the DVM to the 10 amp scale and briefly touch it to the leads from the solar panel. Make sure the reading was not off the scale, if so you'll need a meter with a higher amperage scale, or a 20 amp shunt and you'll have to calculate it yourself (not difficult, I did it in high school). If you have gotten valid readings for both measurements you can simply multiply them to get the wattage. Remember that this will be a real-world measurement, not a laboratory measurement, so it will be lower than the panel's actual rating. Doing it on a bright sunny summer day will produce the closest reading to the panel's specification.
If you are unsure and want to protect your meter, initially angle the panel so it faces about 60° off axis to the sun's rays, that will cut the power of the sun hitting the panel in half. Then measure the short-circuit amps and if it's below 5 amps you can then face the panel directly at the sun and measure it again. Of course if you know your panel has a higher short-circuit current than your meter can handle, you can set the panel 60° off axis and simply multiply the short-circuit current by 2. Barring optical effects that should be accurate.
The height of summer is the best time to do this measurement since at any other time of year the sun will be lower and the sun's rays will be passing through more atmosphere, reducing their intensity. Just turning the panel to directly face the sun does not decrease the amount of atmosphere the sunlight passes through before hitting your panel! Measure the open-circuit voltage, and note the reading. Set the DVM to the 10 amp scale and briefly touch it to the leads from the solar panel. Make sure the reading was not off the scale, if so you'll need a meter with a higher amperage scale, or a 20 amp shunt and you'll have to calculate it yourself (not difficult, I did it in high school). If you have gotten valid readings for both measurements you can simply multiply them to get the wattage. Remember that this will be a real-world measurement, not a laboratory measurement, so it will be lower than the panel's actual rating. Doing it on a bright sunny summer day will produce the closest reading to the panel's specification.
If you are unsure and want to protect your meter, initially angle the panel so it faces about 60° off axis to the sun's rays, that will cut the power of the sun hitting the panel in half. Then measure the short-circuit amps and if it's below 5 amps you can then face the panel directly at the sun and measure it again. Of course if you know your panel has a higher short-circuit current than your meter can handle, you can set the panel 60° off axis and simply multiply the short-circuit current by 2. Barring optical effects that should be accurate.